2x^2-20000=0

Solution for 2x^2-20000=0 equation:

2x^2-20000=0

a = 2; b = 0; c = -20000;
Δ = b2-4ac
Δ = 02-4·2·(-20000)
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-400}{2*2}=\frac{-400}{4}
=-100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+400}{2*2}=\frac{400}{4}
=100
$